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Trigonometry of Indirect Fire
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Old 04 Nov 2007, 23:16   #1 (permalink)
Shas'El
 
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Default Trigonometry of Indirect Fire

One day, which being a nerd I realized how to bring my two loves together.
Trig and Artillery.
And with my new lust to get back into the hobby I thought I'd fill you all in on my dirty little secret.
Tools:
Protracter
Calcuater in Degrees mode
Measuring stick
Scrap Paper if you need to write stuff out
Two points, and an enemy.

Procedure
First, you must name the points and their angles with a capital letter.
Then, name the side opposite the angle the lower case of angles letter.
Next, measure the distance between your points, this will be the side opposite from the enemy.
Using a measuring stick to line up the sides of the triangle, use a protracter to measure the angles of your points with regards to the enemy.
Now, by utilizing thr Interior Angles Therom, determine the angle of the enemy. (IAT states that the sum of all angles in any triangle must be 180º.)
Now you have all you need to use the Sine Law to determine distance from either point to the enemy.
You have the angle and the length of the side opposite it, and the angles of both points.
Now, I will upload pictures soon, but until then I have this example.

I have a Mortar I want to lob into approching Gaunts.
I will use a near by unit of fleeing Guardsmen as my second referance point.
Mortar: A
Guardsmen: B
Gaunts: C
So, that makes the distance between the Mortar and the Guardsmen c, because it is the side opposite of the Gaunts, who are angle C.
Mortar to Gaunts is b, because it is opposite the Guardsmen who are angle B.
Can you guess what the distance between the Guardsmen and the Gaunts is? That's right, a, since it is opposite the Mortar.
Make sense? If not, pm me, as I am moving on.
Now, I measure the c and find it to be 15"(inches).
Then I find the angles from the Mortar and Guardsmen to the Gaunts. Draw a triangle right now to illustrate what I mean.
Once that is done, I find them to be:
A=43º B=23º
So that means that C = 180º-43º-23º (remember the IAT)
C=114º
Write out what we have.
Angles:
A=43º
B=23º
C=114º
Sides:
a=?
b=?
c=15"
Now to find b (Distance from Mortar to Gaunts) we need to use the Sine Law
a/(SinA) = b/(SinB) = c/(SinC)
So, b= (c/[SinC])*SinB
b=(15/Sin114)*Sin23
b=6.5"
b=7"

Mathhammer on the board.
Now, I'm sure about the rules on this, but I've consulted the BBB and it seems to be legit.
Enjoy!
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Old 04 Nov 2007, 23:29   #2 (permalink)
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Default Re: Trigonometry of Indirect Fire

Oh now... trigonometry... how brilliant and absolutely unknown to the rest of mankind... :

I hate to say tis, but you are too late. Guessweapons need no guessing anymore.

Oh, and btw: It is illegal to measure something just because you want to. So your entire "plan" is flawed.

Greetz, Trogdor
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Old 04 Nov 2007, 23:37   #3 (permalink)
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Default Re: Trigonometry of Indirect Fire

The beardy way to do this is to have something in base to base contact and then move it a certain distance away along a certain point and get a known angel from terrain. This seems ridiculously beardy though and you would have to guess the angle, unless you have straight lines on terrain. > Then shoot with the unit you moved away from first. to get that measurement. Know angles of he terrain before.
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Old 05 Nov 2007, 00:33   #4 (permalink)
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Default Re: Trigonometry of Indirect Fire

Ah, well.
Forgive me for posing a new idea..
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Old 05 Nov 2007, 00:36   #5 (permalink)
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Default Re: Trigonometry of Indirect Fire

Hey man dont let them put you down...

I know gamers who still like to guess the ranges (like myself). Good stuff... deserves some karma.


Although yes, the plan will not work in a serious game.
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Old 05 Nov 2007, 00:47   #6 (permalink)
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Default Re: Trigonometry of Indirect Fire

You say you can't measure between points, but you can use a known measurement, like across the board, assuming you're peice is in a table corner.

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Hey man dont let them put you down...
Nah, they aint getting me down.
Some people are just cold and bitter with life, and have to project it upon others. ;D
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Old 05 Nov 2007, 00:53   #7 (permalink)
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Default Re: Trigonometry of Indirect Fire

still interesting even if it's not legal in 40k. And maybe if you play fantasy you could use it with cannons and such?
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Old 05 Nov 2007, 01:54   #8 (permalink)
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Default Re: Trigonometry of Indirect Fire

Quote:
Originally Posted by Mothman
Some people are just cold and bitter with life, and have to project it upon others. ;D
More like correct you in the fact that those rules don't stand anymore, thus you'd have to okay it with the opponent first. No one's being bitter, just informing you.

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Ah, well.
Forgive me for posing a new idea.
I doubt your the first to think of using trig. in a real world problem, let alone 40k (when you did have to guess ranges for those weapons).

FYI BBB is 3rd edition rule book. BGB is 4th edition rulebook. Unless your still using 3rd editions rules ???, in which case then yea the trig. would work fine.
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Old 05 Nov 2007, 11:16   #9 (permalink)
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Default Re: Trigonometry of Indirect Fire

Yes, I still work with 3rd.
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Old 05 Nov 2007, 11:43   #10 (permalink)
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Default Re: Trigonometry of Indirect Fire

off topic, what do BBB and BGB stand for?
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